Precalculus (10th Edition)

Published by Pearson
ISBN 10: 0-32197-907-9
ISBN 13: 978-0-32197-907-0

Chapter 8 - Applications of Trigonometric Functions - 8.2 The Law of Sines - 8.2 Assess Your Understanding - Page 530: 24

Answer

$A= 90^\circ$ $b \approx 0.34$ $c \approx 0.94$

Work Step by Step

Step 1. Using the given conditions, we have $A=180-70-20=90^\circ$ Step 2. Using the Law of Sines, we have $\frac{b}{sin20^\circ}=\frac{c}{sin70^\circ}=\frac{1}{sin90^\circ}$ Step 3. Thus $b=\frac{sin20^\circ}{sin90^\circ} \approx 0.34$ and $c=\frac{sin70^\circ}{sin90^\circ}\approx 0.94$
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