Answer
$A= 25^\circ$
$a \approx8.45$
$c \approx16.38$
Work Step by Step
Step 1. Using the given figure and conditions, we have $A=180-30-125=25^\circ$
Step 2. Using the Law of Sines, we have $\frac{a}{sin25^\circ}=\frac{c}{sin125^\circ}=\frac{10}{sin30^\circ}$
Step 3. Thus $a=\frac{10sin25^\circ}{sin30^\circ}\approx8.45$ and $c=\frac{10sin125^\circ}{sin30^\circ}\approx16.38$
