Precalculus (10th Edition)

Published by Pearson
ISBN 10: 0-32197-907-9
ISBN 13: 978-0-32197-907-0

Chapter 8 - Applications of Trigonometric Functions - 8.2 The Law of Sines - 8.2 Assess Your Understanding - Page 530: 19

Answer

$A =100^\circ$ $b \approx5.24$ $c \approx0.92$

Work Step by Step

Step 1. Using the given conditions, we have $A=180-70-10=100^\circ$ Step 2. Using the Law of Sines, we have $\frac{a}{sin100^\circ}=\frac{c}{sin10^\circ}=\frac{5}{sin70^\circ}$ Step 3. Thus $b=\frac{5sin100^\circ}{sin70^\circ} \approx5.24$ and $c=\frac{5sin10^\circ}{sin70^\circ}\approx0.92$
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