Precalculus (10th Edition)

Published by Pearson
ISBN 10: 0-32197-907-9
ISBN 13: 978-0-32197-907-0

Chapter 8 - Applications of Trigonometric Functions - 8.2 The Law of Sines - 8.2 Assess Your Understanding - Page 530: 15

Answer

$A= 40^\circ$ $a =2$ $c\approx3.06$

Work Step by Step

Step 1. Using the given figure and conditions, we have $A=180-100-40=40^\circ$ Step 2. Using the Law of Sines, we have $\frac{a}{sin40^\circ}=\frac{c}{sin100^\circ}=\frac{2}{sin40^\circ}$ Step 3. Thus $a=\frac{2sin40^\circ}{sin40^\circ}=2$ and $c=\frac{2sin100^\circ}{sin40^\circ}\approx3.06$
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