Precalculus (10th Edition)

Published by Pearson
ISBN 10: 0-32197-907-9
ISBN 13: 978-0-32197-907-0

Chapter 8 - Applications of Trigonometric Functions - 8.2 The Law of Sines - 8.2 Assess Your Understanding - Page 530: 10

Answer

$C =95^\circ$ $a \approx2.84$ $b \approx2.58$

Work Step by Step

Step 1. Using the given figure and conditions, we have $C=180-40-45=95^\circ$ Step 2. Using the Law of Sines, we have $\frac{a}{sin45^\circ}=\frac{b}{sin40^\circ}=\frac{4}{sin95^\circ}$ Step 3. Thus $a=\frac{4sin45^\circ}{sin95^\circ}\approx2.84$ and $b=\frac{4sin40^\circ}{sin95^\circ}\approx2.58$
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