Precalculus (10th Edition)

Published by Pearson
ISBN 10: 0-32197-907-9
ISBN 13: 978-0-32197-907-0

Chapter 8 - Applications of Trigonometric Functions - 8.2 The Law of Sines - 8.2 Assess Your Understanding - Page 530: 5

Answer

$\dfrac{\sin{(A)}}{a}=\dfrac{\sin{(B)}}{b}=\dfrac{\sin{(C)}}{c}$.

Work Step by Step

Recall the Law of Sines for a triangle with sides $a, b, c$ and angles $A, B, C$ where $a$ is opposite angle $A$, $b$ is opposite angle $B$, and $c$ is opposite angle $C$: $\dfrac{\sin{(A)}}{a}=\dfrac{\sin{(B)}}{b}=\dfrac{\sin{(C)}}{c}$.
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