Answer
$\dfrac{\sin{(A)}}{a}=\dfrac{\sin{(B)}}{b}=\dfrac{\sin{(C)}}{c}$.
Work Step by Step
Recall the Law of Sines for a triangle with sides $a, b, c$ and angles $A, B, C$ where $a$ is opposite angle $A$, $b$ is opposite angle $B$, and $c$ is opposite angle $C$:
$\dfrac{\sin{(A)}}{a}=\dfrac{\sin{(B)}}{b}=\dfrac{\sin{(C)}}{c}$.