Precalculus (10th Edition)

Published by Pearson
ISBN 10: 0-32197-907-9
ISBN 13: 978-0-32197-907-0

Chapter 8 - Applications of Trigonometric Functions - 8.2 The Law of Sines - 8.2 Assess Your Understanding - Page 530: 22

Answer

$A= 70^\circ$ $a \approx 10.82$ $c \approx 11.34$

Work Step by Step

Step 1. Using the given conditions, we have $A=180-100-10=70^\circ$ Step 2. Using the Law of Sines, we have $\frac{a}{sin70^\circ}=\frac{c}{sin100^\circ}=\frac{2}{sin10^\circ}$ Step 3. Thus $a=\frac{2sin70^\circ}{sin10^\circ} \approx 10.82$ and $c=\frac{2sin100^\circ}{sin10^\circ}\approx 11.34$
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