Precalculus (10th Edition)

Published by Pearson
ISBN 10: 0-32197-907-9
ISBN 13: 978-0-32197-907-0

Chapter 8 - Applications of Trigonometric Functions - 8.2 The Law of Sines - 8.2 Assess Your Understanding - Page 530: 11

Answer

$B= 45^\circ$ $a \approx3.25$ $c \approx4.23$

Work Step by Step

Step 1. Using the given figure and conditions, we have $B=180-50-85=45^\circ$ Step 2. Using the Law of Sines, we have $\frac{a}{sin50^\circ}=\frac{c}{sin85^\circ}=\frac{3}{sin45^\circ}$ Step 3. Thus $a=\frac{3sin50^\circ}{sin45^\circ}\approx3.25$ and $c=\frac{3sin85^\circ}{sin45^\circ}\approx4.23$
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