Answer
$B= 110^\circ$
$b \approx3.68$
$c \approx1.34$
Work Step by Step
Step 1. Using the given conditions, we have $B=180-50-20=110^\circ$
Step 2. Using the Law of Sines, we have $\frac{b}{sin110^\circ}=\frac{c}{sin20^\circ}=\frac{3}{sin50^\circ}$
Step 3. Thus $b=\frac{3sin110^\circ}{sin50^\circ} \approx3.68$ and $c=\frac{3sin20^\circ}{sin50^\circ}\approx1.34$
