Precalculus (10th Edition)

Published by Pearson
ISBN 10: 0-32197-907-9
ISBN 13: 978-0-32197-907-0

Chapter 8 - Applications of Trigonometric Functions - 8.2 The Law of Sines - 8.2 Assess Your Understanding - Page 530: 14

Answer

$C= 165^\circ$ $a \approx3.35$ $c\approx1.68$

Work Step by Step

Step 1. Using the given figure and conditions, we have $C=180-10-5=165^\circ$ Step 2. Using the Law of Sines, we have $\frac{a}{sin10^\circ}=\frac{b}{sin5^\circ}=\frac{5}{sin165^\circ}$ Step 3. Thus $a=\frac{5sin10^\circ}{sin165^\circ}\approx3.35$ and $c=\frac{5sin5^\circ}{sin165^\circ}\approx1.68$
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