Precalculus (10th Edition)

Published by Pearson
ISBN 10: 0-32197-907-9
ISBN 13: 978-0-32197-907-0

Chapter 8 - Applications of Trigonometric Functions - 8.2 The Law of Sines - 8.2 Assess Your Understanding - Page 530: 13

Answer

$C =95^\circ$ $a \approx6.36$ $c\approx9.86$

Work Step by Step

Step 1. Using the given figure and conditions, we have $C=180-40-45=95^\circ$ Step 2. Using the Law of Sines, we have $\frac{a}{sin40^\circ}=\frac{c}{sin95^\circ}=\frac{7}{sin45^\circ}$ Step 3. Thus $a=\frac{7sin40^\circ}{sin45^\circ}\approx6.36$ and $c=\frac{7sin95^\circ}{sin45^\circ}\approx9.86$
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