Precalculus (10th Edition)

Published by Pearson
ISBN 10: 0-32197-907-9
ISBN 13: 978-0-32197-907-0

Chapter 7 - Analytic Trigonometry - Chapter Review - Review Exercises - Page 506: 62

Answer

$-\frac{24}{25}$

Work Step by Step

Step 1. Letting $cos^{-1}(-\frac{3}{5})=x$, we have $cos(x)=-\frac{3}{5}, sin(x)=\frac{4}{5}$ Step 2. We have $sin(2x)=2sin(x)cos(x)=2(-\frac{3}{5})(\frac{4}{5})=-\frac{24}{25}$
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