Precalculus (10th Edition)

Published by Pearson
ISBN 10: 0-32197-907-9
ISBN 13: 978-0-32197-907-0

Chapter 7 - Analytic Trigonometry - Chapter Review - Review Exercises - Page 506: 59

Answer

$\frac{33}{65}$

Work Step by Step

Step 1. Letting $cos^{-1}\frac{5}{13}=x$, we have $cos(x)=\frac{5}{13}$ and $sin(x)=\frac{12}{13}$ Step 2. Letting $cos^{-1}\frac{4}{5}=y$, we have $cos(y)=\frac{4}{5}$ and $sin(y)=\frac{3}{5}$ Step 3. We have $sin(x-y)=sin(x)cos(y)-cos(x)sin(y)=(\frac{12}{13})(\frac{4}{5})-(\frac{5}{13})(\frac{3}{5})=\frac{33}{65}$
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