Answer
See below.
Work Step by Step
$LHS=\frac{sin(3\theta)cos(\theta)-sin(\theta)cos(3\theta)}{sin(2\theta)}=\frac{sin(3\theta-\theta)}{sin(2\theta)}=1=RHS$
Precalculus (10th Edition)
by Sullivan, Michael
Published by
Pearson
ISBN 10:
0-32197-907-9
ISBN 13:
978-0-32197-907-0
Chapter 7 - Analytic Trigonometry - Chapter Review - Review Exercises - Page 506: 42
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