Precalculus (10th Edition)

Published by Pearson
ISBN 10: 0-32197-907-9
ISBN 13: 978-0-32197-907-0

Chapter 7 - Analytic Trigonometry - Chapter Review - Review Exercises - Page 506: 45

Answer

$\frac{\sqrt 6-\sqrt 2}{4}$

Work Step by Step

$sin(165^\circ)=sin(120^\circ+45^\circ)=sin(120^\circ)cos(45^\circ)+cos(120^\circ)sin(45^\circ)=(\frac{\sqrt 3}{2})(\frac{\sqrt 2}{2})+(-\frac{1}{2})(\frac{\sqrt 2}{2})=\frac{\sqrt 6-\sqrt 2}{4}$
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