Precalculus (10th Edition)

Published by Pearson
ISBN 10: 0-32197-907-9
ISBN 13: 978-0-32197-907-0

Chapter 7 - Analytic Trigonometry - Chapter Review - Review Exercises - Page 506: 40

Answer

See below.

Work Step by Step

$LHS=2cot(\theta)cot(2\theta)=2cot(\theta)(\frac{1-tan^2(\theta)}{2tan(\theta)})=\frac{1-tan^2(\theta)}{tan^2(\theta)}=cot^2\theta-1=RHS$
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