Answer
$\sqrt 2-1$
Work Step by Step
$tan(\frac{\pi}{8})=tan(\frac{\pi/4}{2})=\frac{1-cos(\frac{\pi}{4})}{sin(\frac{\pi}{4})}=\frac{1-\frac{\sqrt 2}{2}}{\frac{\sqrt 2}{2}}=\sqrt 2-1$
Precalculus (10th Edition)
by Sullivan, Michael
Published by
Pearson
ISBN 10:
0-32197-907-9
ISBN 13:
978-0-32197-907-0
Chapter 7 - Analytic Trigonometry - Chapter Review - Review Exercises - Page 506: 51
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