Precalculus (10th Edition)

Published by Pearson
ISBN 10: 0-32197-907-9
ISBN 13: 978-0-32197-907-0

Chapter 7 - Analytic Trigonometry - Chapter Review - Review Exercises - Page 506: 34

Answer

See below.

Work Step by Step

$LHS=csc\theta-sin\theta=\frac{1}{sin\theta}-sin\theta=\frac{1-sin^2\theta}{sin\theta}=\frac{cos^2\theta}{sin\theta}=cos\theta cot\theta=RHS$
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