Answer
$\sqrt {1-u^2}$
Work Step by Step
Step 1. Letting $sin^{-1}u=t$, we have $sin(t)=u$
Step 2. Form a right triangle of $y=u, r=1, x=\sqrt {1-u^2}$ with $|t|$ facing $y$.
Step 3. We have $cos(sin^{-1}u)=cos(t)=\sqrt {1-u^2}$
Precalculus (10th Edition)
by Sullivan, Michael
Published by
Pearson
ISBN 10:
0-32197-907-9
ISBN 13:
978-0-32197-907-0
Chapter 7 - Analytic Trigonometry - Chapter Review - Review Exercises - Page 506: 26
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