Answer
See below.
Work Step by Step
$LHS=\frac{1-sin\theta}{sec\theta}=\frac{1-sin\theta}{1/cos\theta}=cos\theta(1-sin\theta)$
$RHS=\frac{cos^3\theta}{1+sin\theta}=\frac{cos\theta(1-sin^2\theta)}{1+sin\theta}=cos\theta(1-sin\theta)=LHS$
Precalculus (10th Edition)
by Sullivan, Michael
Published by
Pearson
ISBN 10:
0-32197-907-9
ISBN 13:
978-0-32197-907-0
Chapter 7 - Analytic Trigonometry - Chapter Review - Review Exercises - Page 506: 35
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