Answer
$ \frac{2\sqrt 3}{3}$
Work Step by Step
$sec[tan^{-1}(\frac{\sqrt 3}{3})]=sec[\frac{\pi}{6}]=\frac{2\sqrt 3}{3}$.
Precalculus (10th Edition)
by Sullivan, Michael
Published by
Pearson
ISBN 10:
0-32197-907-9
ISBN 13:
978-0-32197-907-0
Chapter 7 - Analytic Trigonometry - Chapter Review - Review Exercises - Page 506: 21
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