Precalculus (10th Edition)

Published by Pearson
ISBN 10: 0-32197-907-9
ISBN 13: 978-0-32197-907-0

Chapter 7 - Analytic Trigonometry - Chapter Review - Review Exercises - Page 506: 33

Answer

See below.

Work Step by Step

$LHS=\frac{csc\theta}{1+csc\theta}\times\frac{sin\theta}{sin\theta}=\frac{1}{sin\theta+1}$ $RHS=\frac{1-sin\theta}{1-sin^2\theta}=\frac{1}{1+sin\theta}=LHS$
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