Precalculus (10th Edition)

Published by Pearson
ISBN 10: 0-32197-907-9
ISBN 13: 978-0-32197-907-0

Chapter 6 - Trigonometric Functions - 6.2 Trigonometric Functions: Unit Circle Approach - 6.2 Assess Your Understanding: 99

Answer

$\frac{3}{4}.$

Work Step by Step

$[f(\theta)]^2=[sin (60^{O})]^2=[sin\frac{\pi}{3}]^2=[\frac{\sqrt3}{2}]^2=\frac{3}{4}.$
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