Precalculus (10th Edition)

Published by Pearson
ISBN 10: 0-32197-907-9
ISBN 13: 978-0-32197-907-0

Chapter 6 - Trigonometric Functions - 6.2 Trigonometric Functions: Unit Circle Approach - 6.2 Assess Your Understanding - Page 379: 25



Work Step by Step

We know that $csc$ has a period of $2\pi$, hence first we try and find a value where the argument is between $0$ and $2/pi$. Therefore $csc(\frac{11\pi}{2})=csc(\frac{(11-4)\pi}{2})=csc(\frac{7\pi}{2})=csc(\frac{(7-4)\pi}{2})=csc(\frac{3\pi}{2})=-1.$
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