Precalculus (10th Edition)

Published by Pearson
ISBN 10: 0-32197-907-9
ISBN 13: 978-0-32197-907-0

Chapter 6 - Trigonometric Functions - 6.2 Trigonometric Functions: Unit Circle Approach - 6.2 Assess Your Understanding - Page 379: 95

Answer

$\frac{\sqrt3}{2}.$

Work Step by Step

$f(\theta)=sin (60^{O})=sin\frac{\pi}{3}=\frac{\sqrt3}{2}.$
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