Answer
$-1$
Work Step by Step
We know that $sec$ has a period of $2\pi$, hence first we try and find a value where the argument is between $\frac{-\pi}{2}$ and $\frac{3\pi}{2}$. Therefore $sec(-\pi)=sec(-\pi+2\pi)=sec(\pi)=-1$
Precalculus (10th Edition)
by Sullivan, Michael
Published by
Pearson
ISBN 10:
0-32197-907-9
ISBN 13:
978-0-32197-907-0
Chapter 6 - Trigonometric Functions - 6.2 Trigonometric Functions: Unit Circle Approach - 6.2 Assess Your Understanding - Page 379: 29
Update this answer!
You can help us out by revising, improving and updating this answer.
Update this answerAfter you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.
