Precalculus (10th Edition)

Published by Pearson
ISBN 10: 0-32197-907-9
ISBN 13: 978-0-32197-907-0

Chapter 6 - Trigonometric Functions - 6.2 Trigonometric Functions: Unit Circle Approach - 6.2 Assess Your Understanding - Page 379: 45



Work Step by Step

RECALL: (1) $\csc{\theta}=\frac{1}{\sin{\theta}}$ (2) $\cot{\theta} = \frac{\cos{\theta}}{\sin{\theta}}$ With $\sin{\frac{\pi}{2}}=1$ and $\cos{\frac{\pi}{2}}=0$, then $\csc\dfrac {\pi }{2}+\cot \dfrac {\pi }{2} \\=\dfrac {1}{\sin \dfrac {\pi }{2}}+\dfrac {\cos \dfrac {\pi }{2}}{\sin \dfrac {\pi }{2}} \\=\dfrac {1}{1}+\dfrac {0}{1} \\=1+0 \\=1$
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