Precalculus (10th Edition)

Published by Pearson
ISBN 10: 0-32197-907-9
ISBN 13: 978-0-32197-907-0

Chapter 6 - Trigonometric Functions - 6.2 Trigonometric Functions: Unit Circle Approach - 6.2 Assess Your Understanding - Page 379: 50

Answer

$sin(t) =-\frac{\sqrt 3}{2}$, $cos(t) =-\frac{1}{2}$, $tan(t) =\sqrt 3$, $cot(t) =\frac{\sqrt 3}{3}$, $sec(t) =-2$, $csc(t) =-\frac{2\sqrt 3}{3}$.

Work Step by Step

Given $t=240^\circ$, the terminal side is in quadrant III and $60^\circ$ to the $-x$-axis , we have: $sin(t)=y=-\frac{\sqrt 3}{2}$, $cos(t)=x=-\frac{1}{2}$, $tan(t)=\frac{y}{x}=\sqrt 3$, $cot(t)=\frac{x}{y}=\frac{\sqrt 3}{3}$, $sec(t)=\frac{1}{x}=-2$, $csc(t)=\frac{1}{y}=-\frac{2\sqrt 3}{3}$.
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