Precalculus (10th Edition)

Published by Pearson
ISBN 10: 0-32197-907-9
ISBN 13: 978-0-32197-907-0

Chapter 6 - Trigonometric Functions - 6.2 Trigonometric Functions: Unit Circle Approach - 6.2 Assess Your Understanding - Page 379: 48

Answer

$sin(t) =\frac{1}{2}$, $cos(t) =-\frac{\sqrt 3}{2}$, $tan(t) =-\frac{\sqrt 3}{3}$, $cot(t) =-\sqrt 3$, $sec(t) =-\frac{2\sqrt 3}{3}$, $csc(t) =2$.

Work Step by Step

Given $t=\frac{5\pi}{6}$, the terminal side is in quadrant II and $\frac{\pi}{6}$ to the $-x$-axis , we have: $sin(t)=y=\frac{1}{2}$, $cos(t)=x=-\frac{\sqrt 3}{2}$, $tan(t)=\frac{y}{x}=-\frac{\sqrt 3}{3}$, $cot(t)=\frac{x}{y}=-\sqrt 3$, $sec(t)=\frac{1}{x}=-\frac{2\sqrt 3}{3}$, $csc(t)=\frac{1}{y}=2$.
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.