Precalculus (10th Edition)

Published by Pearson
ISBN 10: 0-32197-907-9
ISBN 13: 978-0-32197-907-0

Chapter 6 - Trigonometric Functions - 6.2 Trigonometric Functions: Unit Circle Approach - 6.2 Assess Your Understanding - Page 379: 36

Answer

$\frac{\sqrt3}{2}$.

Work Step by Step

$\tan{45^\circ}\cdot\cos{30^\circ}=\tan{\frac{\pi}{4}}\cdot\cos{\frac{\pi}{6}}=1\cdot\frac{\sqrt3}{2}=\frac{\sqrt3}{2}$.
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