Precalculus (10th Edition)

Published by Pearson
ISBN 10: 0-32197-907-9
ISBN 13: 978-0-32197-907-0

Chapter 6 - Trigonometric Functions - 6.2 Trigonometric Functions: Unit Circle Approach - 6.2 Assess Your Understanding - Page 379: 59

Answer

$sin(t) =-\frac{\sqrt 2}{2}$, $cos(t) =-\frac{\sqrt 2}{2}$, $tan(t) =1$, $cot(t) =1$, $sec(t) =-\sqrt 2$, $csc(t) = -\sqrt 2$.

Work Step by Step

Given $t=-135^\circ$, the terminal side is in quadrant III and $t_0=45^\circ$ to the $-x$-axis , we have: $sin(t)=-sin(t_0)=-\frac{\sqrt 2}{2}$, $cos(t)=-cos(t_0)=-\frac{\sqrt 2}{2}$, $tan(t)=tan(t_0)=1$, $cot(t)=cot(t_0)=1$, $sec(t)=-sec(t_0)=-\sqrt 2$, $csc(t)=-csc(t_0)= -\sqrt 2$.
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