Precalculus (10th Edition)

Published by Pearson
ISBN 10: 0-32197-907-9
ISBN 13: 978-0-32197-907-0

Chapter 6 - Trigonometric Functions - 6.2 Trigonometric Functions: Unit Circle Approach - 6.2 Assess Your Understanding - Page 379: 46

Answer

$-2$

Work Step by Step

RECALL: (1) $\sec{\theta}=\frac{1}{\cos{\theta}}$ (2) $\csc{\theta} = \frac{1}{\sin{\theta}}$ With $\sin{\frac{\pi}{2}}=1$ and $\cos{\pi}=-1$, then $\sec\pi -csc{\frac {\pi }{2}} \\=\dfrac {1}{\cos \pi }-\dfrac {1}{\sin{\frac {\pi }{2}}} \\=\dfrac {1}{-1}-\dfrac {1}{1} \\=-1-1 \\=-2$
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