Answer
$sin(\theta) =\frac{3}{5}$,
$cos(\theta) =\frac{4}{5}$,
$tan(\theta) =\frac{3}{4}$,
$cot(\theta) =\frac{4}{3}$,
$sec(\theta) =\frac{5}{4}$,
$csc(\theta) =\frac{5}{3}$.
Work Step by Step
We can multiply the coordinates with $12$ to get another point on the same terminal $x=4,y=3$, the terminal side is in quadrant I with $r=\sqrt {x^2+y^2}=5$, we have:
$sin(\theta)=\frac{y}{r}=\frac{3}{5}$,
$cos(\theta)=\frac{x}{r}=\frac{4}{5}$,
$tan(\theta)=\frac{y}{x}=\frac{3}{4}$,
$cot(\theta)=\frac{x}{y}=\frac{4}{3}$,
$sec(\theta)=\frac{r}{x}=\frac{5}{4}$,
$csc(\theta)=\frac{r}{y}=\frac{5}{3}$.
