Precalculus (10th Edition)

Published by Pearson
ISBN 10: 0-32197-907-9
ISBN 13: 978-0-32197-907-0

Appendix A - Review - A.5 Rational Expressions - A.5 Assess Your Understanding - Page A41: 26

Answer

$\dfrac{(x-1)(x^2+1)+x^4}{x^3(x^2+1)}$

Work Step by Step

The LCD is $x^3(x^2+1)$. Make the expressions similar by multiplying the numerators and denominators by $x^2+1$ and $x^3$, respectively, to obtain: $=\dfrac{x-1}{x^3}\cdot \dfrac{x^2+1}{x^2+1}+\dfrac{x}{x^2+1}\cdot \dfrac{x^3}{x^3}$ $=\dfrac{(x-1)(x^2+1)}{x^3(x^2+1)}+\dfrac{x^4}{x^3(x^2+1)}$ Add numerators and retain the denominator to obtain: $=\dfrac{(x-1)(x^2+1)+x^4}{x^3(x^2+1)}$
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