Precalculus (10th Edition)

Published by Pearson
ISBN 10: 0-32197-907-9
ISBN 13: 978-0-32197-907-0

Appendix A - Review - A.5 Rational Expressions - A.5 Assess Your Understanding - Page A41: 10

Answer

$\dfrac{5x+8}{3}, \space x\ne0$

Work Step by Step

Note that $\dfrac{15x^2+24x}{3x^2}=\dfrac{3x(5x)+3x(8)}{3x\cdot x}$ Factor out $3x$ in the numerator. $=\dfrac{3x(5x+8)}{3x\cdot x}$ Cancel common factor $3x$: $=\dfrac{5x+8}{3}, \space x\ne0$ Hence, the lowest term is $\dfrac{5x+8}{3}, \space x\ne0$.
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