Answer
$\dfrac{(x+2)(x-2)}{2x-3}$
Work Step by Step
Add numerators because denominators are same.
$\dfrac{x^2-4}{2x-3}$
$=\dfrac{x^2-2^2}{2x-3}$
Factor each polynomial completely.
Use special formula $a^2-b^2=(a+b)(a-b)$.
$=\dfrac{(x+2)(x-2)}{2x-3}$
