Answer
$\dfrac{3(x^2-3)}{2x-1}$
Work Step by Step
The denominators are same so just subtract the numerators and retain the denominator to obtain:
$\dfrac{3x^2-9}{2x-1}$
Factor each the numerator.
$=\dfrac{3(x^2-3)}{2x-1}$
Precalculus (10th Edition)
by Sullivan, Michael
Published by
Pearson
ISBN 10:
0-32197-907-9
ISBN 13:
978-0-32197-907-0
Appendix A - Review - A.5 Rational Expressions - A.5 Assess Your Understanding - Page A41: 24
Update this answer!
You can help us out by revising, improving and updating this answer.
Update this answerAfter you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.
