#### Answer

330

#### Work Step by Step

The number of possible combinations if r items are taken from n items is
nCr = $\frac{n!}{r!(n-r)!}$
11C4 = $\frac{11!}{4!(11-4)!}$
=$\frac{11!}{4!7!}$
=$\frac{11*10*9*8*7!}{4!7!}$
==$\frac{11*10*9*8}{4*3*2*1}$
=330