#### Answer

210

#### Work Step by Step

The number of possible combinations if r items are taken from n items is
nCr = $\frac{n!}{r!(n-r)!}$
10C6 = $\frac{10!}{6!(10-6)!}$
=$\frac{10!}{6!4!}$
=$\frac{10*9*8*7*6!}{6!4!}$
=$\frac{10*9*8*7}{4*3*2*1}$ = 210

Published by
Pearson

ISBN 10:
0321867327

ISBN 13:
978-0-32186-732-2

210

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