#### Answer

1

#### Work Step by Step

The number of possible combinations if r items are taken from n items is
nCr = $\frac{n!}{r!(n-r)!}$
7C7 = $\frac{7!}{7!(7-7)!}$
=$\frac{7!}{7!0!}$
0!=1, so the answer is 1.

Published by
Pearson

ISBN 10:
0321867327

ISBN 13:
978-0-32186-732-2

1

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