#### Answer

792

#### Work Step by Step

The number of possible combinations if r items are taken from n items is
nCr = $\frac{n!}{r!(n-r)!}$
12C5 = $\frac{12!}{5!(12-5)!}$
=$\frac{12!}{5!7!}$
=$\frac{12*11*10*9*8*7!}{5!7!}$
=$\frac{12*11*10*9*8}{5*4*3*2*1}$ = 792