#### Answer

1

#### Work Step by Step

The number of possible combinations if r items are taken from n items is
nCr = $\frac{n!}{r!(n-r)!}$
6C0 = $\frac{6!}{0!(6 -0)!}$
=$\frac{6!}{0!6!}$
0!=1, so the expression reduces to 1.

Published by
Pearson

ISBN 10:
0321867327

ISBN 13:
978-0-32186-732-2

1

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