#### Answer

8

#### Work Step by Step

The number of possible combinations if r items are taken from n items is
nCr = $\frac{n!}{r!(n-r)!}$
8C1 = $\frac{8!}{1!(8-1)!}$
=$\frac{8!}{1!7!}$
=$\frac{8*7!}{1!7!}$
Therefore, the result is 8.

Published by
Pearson

ISBN 10:
0321867327

ISBN 13:
978-0-32186-732-2

8

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