#### Answer

6

#### Work Step by Step

The number of possible combinations if r items are taken from n items is:
nCr = $\frac{n!}{r!(n-r)!}$
6C5 = $\frac{6!}{5!(6-5)!}$
=$\frac{6!}{5!}$
=$\frac{6*5!}{5!}$
We cancel out 5!, leaving us with 6.

Published by
Pearson

ISBN 10:
0321867327

ISBN 13:
978-0-32186-732-2

6

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