Answer
$360$ ways
Work Step by Step
In a race, the position of finishing matters,
order matters, so this problem involves permutations.
${}_{n}P_{r}=\displaystyle \frac{n!}{(n-r)!}$
${}_{6}P_{4}=\displaystyle \frac{6!}{(6-4)!}=6\times 5\times 4\times 3=360$
