## Thinking Mathematically (6th Edition)

$360$ ways
In a race, the position of finishing matters, order matters, so this problem involves permutations. ${}_{n}P_{r}=\displaystyle \frac{n!}{(n-r)!}$ ${}_{6}P_{4}=\displaystyle \frac{6!}{(6-4)!}=6\times 5\times 4\times 3=360$