#### Answer

8

#### Work Step by Step

The number of possible combinations if r items are taken from n items is
nCr = $\frac{n!}{r!(n-r)!}$
8C7 = $\frac{8!}{7!(8-7)!}$
=$\frac{8!}{7!}$
=$\frac{8*7!}{7!}$
Since 7! is both in the numerator and the denominator, we cancel it out, leaving us with 8.