Answer
$\frac{dy}{dx}=-\frac{(y+2)}{(x+3)}$
Work Step by Step
We are given that:
$xy+2x+3y=1$
differentiate the above term:
$y+x\frac{dy}{dx}+2+3\frac{dy}{dx}=0$
$(x+3)\frac{dy}{dx}=-(y+2)$
$\frac{dy}{dx}=-\frac{(y+2)}{(x+3)}$
University Calculus: Early Transcendentals (3rd Edition)
by Hass, Joel R.; Weir, Maurice D.; Thomas Jr., George B.
Published by
Pearson
ISBN 10:
0321999584
ISBN 13:
978-0-32199-958-0
Chapter 3 - Practice Exercises - Page 202: 65
Update this answer!
You can help us out by revising, improving and updating this answer.
Update this answerAfter you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.
