Answer
$\frac{dy}{dx}=\frac{-9}{2}{(5x^2+\sin{2x})^{\frac{-5}{2}}}(10x+2\cos{2x})$
Work Step by Step
$y=\frac{3}{(5x^2+\sin{2x})^{\frac{3}{2}}}=3{(5x^2+\sin{2x})^{\frac{-3}{2}}}$
on differentiating both sides:
$\frac{dy}{dx}=3\frac{-3}{2}{(5x^2+\sin{2x})^{\frac{-5}{2}}}\frac{(d(5x^2+\sin{2x}))}{dx}$
$\frac{dy}{dx}=\frac{-9}{2}{(5x^2+\sin{2x})^{\frac{-5}{2}}}(10x+2\cos{2x})$
