University Calculus: Early Transcendentals (3rd Edition)

Published by Pearson
ISBN 10: 0321999584
ISBN 13: 978-0-32199-958-0

Chapter 3 - Practice Exercises - Page 202: 59



Work Step by Step

Given $y=t\tan^{-1}{t}-\frac{1}{2}\ln{t}$ On differentiating both sides: $\frac{dy}{dt}=\frac{d(t\tan^{-1}{t}-\frac{1}{2}\ln{t})}{dt}$ $\frac{dy}{dt}=(\frac{t}{1+{t^2}}+\tan^{-1}{t}-\frac{1}{2t})$
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