University Calculus: Early Transcendentals (3rd Edition)

Published by Pearson
ISBN 10: 0321999584
ISBN 13: 978-0-32199-958-0

Chapter 3 - Practice Exercises - Page 202: 52



Work Step by Step

Given $y=\sqrt{2}x^{-\sqrt{2}}$ On differentiating both sides: $\frac{dy}{dt}=-\sqrt{2}\sqrt{2}x^{-\sqrt{2}-1}$ $\frac{dy}{dt}=-2x^{-\sqrt{2}-1}$
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